If the length of the transverse tangent is 8 cm, then calculate the centre distance (in cm) of the two circles with radii 7 cm and 3 cm.
PQ and RS are traverse common tangents
Let the distance between centres AC = $$d$$ cm
Then, length of traverse common tangent is given by = $$(PQ)^2=(RS)^2=d^2-(r_1+r_2)^2$$
=> $$(8)^2=d^2-(7+3)^2$$
=> $$d^2=100+64=164$$
=> $$d=\sqrt{164}$$ cm
=> Ans - (C)
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