Question 6

The base and height of a right angled triangle is 12 cm and 5 cm respectively. Find the circum-radius (in cm) of the triangle.

Solution

Length of base and height of triangle = 12 and 5 cm

=> Let length of hypotenuse = $$x$$ cm

=> $$(x)^2=(12)^2+(5)^2$$

=> $$(x)^2=144+25=169$$

=> $$x=\sqrt{169}=13$$ cm

Also, the circumcentre of a right angled triangle lies on its hypotenuse, thus circumradius = $$\frac{1}{2}\times$$ (hypotenuse)

= $$\frac{1}{2}\times13=6.5$$ cm

=> Ans - (C)

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