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Question 60
Among 100 students, $$x_1$$ have birthdays in January, $$X_2$$ have birthdays in February, and so on. If $$x_0=max(x_1,x_2,....,x_{12})$$, then the smallest possible value of $$x_0$$ is
Solution
$$x_0=max(x_1,x_2,....,x_{12})$$
$$x_0$$ will be minimum if x1,x2...x12 are close to each other
100/12=8.33
.'. max$$(x_1,x_2,....,x_{12})$$ will be minimum if $$(x_1,x_2,....,x_{12})$$=(9,9,9,9,8,8,8,8,8,8,8,8,)
.'. Option B is correct.
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