Question 65

Two chords AB and CD ofa circle intersect at a point P inside the circle. If AB = 7 cm, PC = 2 cm and AP = 4 cm,then CD is equal to:

Name: Two chords AB and CD ofa circle intersect at a point P inside the circle. If AB = 7 cm, PC = 2 cm and AP = 4 cm,then CD is equal to:
Uploaded: April 8, 2021, 10:29 a.m.
Duration: 2 min 16 s
Description: Two chords AB and CD ofa circle intersect at a point P inside the circle. If AB = 7 cm, PC = 2 cm and AP = 4 cm,then CD is equal to:

Solution

When two chords intersect at point P inside the circle then $$PA\times\ PB=PC\times\ PD$$

$$4\times3=PD\times2$$

$$PD=6$$

Therefore, CD= PC+PD=2+6=8 cm.

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SSC CGL 11 June 2019 Shift-3

Two chords AB and CD ofa circle intersect at a point P inside the circle. If AB = 7 cm, PC = 2 cm and AP = 4 cm,then CD is equal to:

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