Question 75

If $$A = 2 \div 3 \times 4, B = 3 of 4 + (7 - 2)$$ and $$C = 4 + 5 - 6$$, then what is the value of $$A + B + C$$?

Solution

$$A = 2 \div 3 \times 4, B = 3 of 4 + (7 - 2)$$ and $$C = 4 + 5 - 6$$

First solve bracket then apply bodmas rule

$$A =\frac {8}{3} $$

B = $$3 of 4 + (7 - 2)$$

= $$12 + 5$$

= 17

C = $$4 + 5 - 6$$

=3

Then

A+B +C= $$\frac {8}{3} $$ +17 +3

=$$\frac {68}{3}$$

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