Every day a person walks at a constant speed, $$V_1$$ for 30 minutes. On a particular day, after walking for 10 minutes at $$V_1$$, he rested for 5 minutes. He finished the remaining distance of his regular walk at a constant speed, $$V_2$$, in another 30 minutes. On that day, find the ratio of $$V_2$$ and his average speed (i.e., total distance covered /total time taken including resting time).
The man walks with a speed of V1 for 30 minutes.Â
=> Distance covered = 30*V1.
On a particular day, he walks for 10 minutes at V1, takes a rest of 5 minutes, and then covers the distance by walking at V2 for 30 minutes.Â
=> 10*V1 + 30*V2 = 30*V1
20*V1 = 30*V2
V1 = 1.5V2---------(1)
=> Total distance = 30*1.5*V2 = 45V2.
Now, we know that the person took 10 + 5 + 30 = 45 minutes to cover the entire distance.Â
=> Average speed = 45V2/45 = V2.
Ratio of V2 and the average speed = 1:1.
Therefore, option A is the right answer.Â