Question 9

In what ratio must a mixture of 20% milk strength be mixed with that of 60% milk strength so as to get a new mixture of 25% milk strength ?

Solution

Let the ratio in which 20% milk be mixed with that of 60% milk = $$x:y$$

According to ques,

=> $$20x+60y=25(x+y)$$

=> $$20x+60y=25x+25y$$

=> $$25x-20x=60y-25y$$

=> $$5x=35y$$

=> $$\frac{x}{y}=\frac{35}{5}=7$$

$$\therefore$$ Required ratio = 7 : 1

=> Ans - (A)

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