Question 94

Three parallel lines are cut by two transversals as shown in the given figure. If AB = 2 cm, BC = 4 cm and DE = 1.5 cm, then the length of EF is:

Solution

AD is parallel to BE is parallel to CF

$$\ \frac{\ AB}{BC}\ =\ \ \frac{\ DE}{EF}$$ [Basic proportionality theorem]

$$\ \frac{\ 2}{4}\ =\ \ \frac{\ 1.5}{EF}$$

EF = 3 cm

B is the correct answer.

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