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Question 18
A roller is 4m long and has a diameter of 0.7m. It takes exactly 2000 rotations of the roller to level a road. If the cost of using the roller is Rs.4 per square metres, then the total cost of levelling the roadis :
Assume, $$\pi=\frac{22}{7}$$
Solution
Curved Surface area of roller = $$2\pi\ rh$$
Cost = Area covered* cost per meter square
so we get total cost = $$2\times\ \frac{22}{7}\times\ \frac{7}{20}\times\ 4\times\ 4\times\ 2000$$
=Rs 70,400
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