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Question 32
A watch which gains uniformly is 2 minutes slow at 10:00 AM on Monday and is $$2\frac{1}{2}$$ minutes fast at 1:00 PM the following day. When did it show the correct time ?
Solution
Between 10 A.M. on Monday to 1:00 PM the following day, the watch gained 4.5 minutes.
So, in 27 hours, the watch gained 4.5 minutes.
It means, the watch gained every minute in every $$\dfrac{27}{4.5}=6$$ hours
At 10:00 AM, the watch was 2 minutes slow, so the watch would be showing accurate time in next 2*6 = 12 hours i.e. 10:00 P.M.
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