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Find the range of values of real number x for which the inequality (x + 2) (x + 5) > 40 holds
correct answer:-5
The minimum value of $$\frac{3(6+x)(x+12)}{2(4+x)}$$, Where $$x>-4$$ is
correct answer:-2
If $$y^2$$ + 3y - 18 ≥ 0, which of the following is true?
correct answer:-4
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