Find the range of values of real number x for which the inequality (x + 2) (x + 5) > 40 holds
$$(x+2)(x+5) > 40$$
$$x^2+7x+10>40$$
$$x^2+7x-30>0$$
$$\left(x+10\right)\left(x-3\right)>0$$
Range of x is $$\left(-\infty\ ,-10\right)U\left(3,\infty\right)$$
As none of the given options is same as above, this question is removed from official CMAT exam.
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