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Following 3 questions are based on the information given below.
There are 240 students in an engineering college. Each student opted for exactly one of
three specialisations among Computer Science, Mechanical and Electronics. The total
number of students who opted for Computer Science and Electronics is equal to the
number of students who opted for Mechanical. 42·5 % students who opted for Mechanical
are girls. The number of girls who opted for Computer Science is one-third the number of
boys who opted for Mechanical. The difference between the number of boys who opted for
Electronics and the number of girls who opted for Computer Science is equal to the
difference between the number of boys who opted for Computer Science and the number
of girls who opted for Electronics. The number of girls who opted for Electronics is 28.
Let C be Computer Science, M be Mechanical, and E be Electronics
Total number of students = C + M + E = 240 - (1)
It is also given that C + E = M - (2)
M = Girls in M + Boys in M
Girls in M = $$\dfrac{42.5}{100}M$$
Boys in M = $$\dfrac{57.5}{100}M$$
C = Girls in C + Boys in C
Girls in C = $$\dfrac{1}{3}\times\ \dfrac{57.5}{100}M\ =\ \dfrac{57.5}{300}M$$
Boys in E - Girls in C = Boys in C - Girls in E
Boys in E + Boys in C = Girls in C + Boys in C
E = C - (3)
Girls in E = 28.
From (1), (2) and (3) we get
C + M + E = C + 2C + C = 240
4C = 240
C = E = 60
M = 120
Girls in M = $$\dfrac{42.5}{100}M$$ = $$\dfrac{42.5}{100}\ \times\ 120\ =\ 51$$
Girls in C = $$\dfrac{57.5}{300}\ \times\ 120\ =\ 23$$
Girls in E = 28
Total number of Girls = 51 + 23 + 28 = 102
The correct answer is option C.
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