Question 11

If $$x^{2}-3x+2$$ is a factor of $$x^{4}-px^{2}+q$$, then (p,q) =

Solution

We have :
$$f\left(x\right)\ =\ x^4-px^2+q$$
Now $$x^2-3x+2\ =\ \left(x-2\right)\left(x-1\right)\ $$ is a factor of f(x) 
so we can say f(2) = f(1) =0 
substituting we get
1-p+q =0
p-q =1  
and 16-4p+q =0
4p-q =16
solving we get
p=5 and q =4

Video Solution

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