Please enter the following details
Free Daily Targets & Mocks
Study Material & Formulas PDFs
1 on 1 Mentorship
Question 13
If a 30 meter ladder is placed against a wall such that it just reaches the top of the wall, if the horizontal distance between the wall and the base of the ladder is 1/3rd of the length of ladder, then the height of wall is :
Solution
AC is ladder, C is base of ladder, AB is wall
Given AC = 30 m and BC = $$\frac{1}{3}AC$$ = $$\frac{1}{3}\left(30\right)$$ = 10 m
Applying pythagoras theorem,
$$AB^2+\ BC^2=\ AC^2$$
$$AB^2$$ = $$30^2-10^2$$ = 800
AB = $$20\sqrt{\ 2}$$
Answer is option B.
Video Solution
Create a FREE account and get:
- All Quant Formulas and shortcuts PDF
- 40+ previous papers with detau solutions PDF
- Top 500 MBA exam Solved Questions for Free
CMAT Quant Questions | CMAT Quantitative Ability
CMAT Averages, Ratio and Proportion QuestionsCMAT Venn Diagrams QuestionsCMAT Quadratic Equations QuestionsCMAT Linear Equations QuestionsCMAT Progressions and Series Questions
CMAT DILR Questions | LRDI Questions For CMAT
CMAT Arrangement QuestionsCMAT Logical Reasoning QuestionsCMAT Set Theory QuestionsCMAT Charts QuestionsCMAT Data Interpretation Basics Questions
