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Solution
Given x = $$\sqrt[6]{5}$$ and y = $$\sqrt[5]{4}$$
which can also be written as x = $$5^{\frac{5}{30}}$$ and y = $$4^{\frac{6}{30}}$$
which can be further written as x = $$\sqrt[30]{5^5}$$ and y = $$\sqrt[30]{4^6}$$
As we know $$4^6 > 5^5$$
$$\Rightarrow \sqrt[30]{4^6} > \sqrt[30]{5^5} $$
$$\Rightarrow$$ y > x
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