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Question 18
Five years ago, the average age of A,B,C and D was 45 years. By including X in the present lot their present average changes to 49 years. What is the present age of X?
Solution
Sum of ages of A, B, C and D five years ago = $$45\times4=180$$
Sum of their present ages = $$180+(5\times4)=200$$
Sum of present ages of all five (including X) = $$49\times5=245$$
=> Present age of X = $$245-200=45$$ years
=> Ans - (B)
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