If 26 horses or 20 bullocks eat up the fodder in store in 170 days, in what time will 10 horses and 8 bullocks finish the same quantity of fodder?
Let amount eaten by each horse and each bullock in one day be 'h' units and 'b' units respectively.
So Total fodder = Total effciency$$\times$$Total number of days
$$\Rightarrow$$ Total work = 26$$\times$$h$$\times$$170 = 20$$\times$$b$$\times$$170
$$\Rightarrow$$ b = 1.3h............(1)
The amount of fodder eaten by 10 horses and 8 bullocks in one day = 10h + 8b = 10h + 8(1.3h) = 20.4h
Time taken by them to eat the same amount of fodder = total fodder/amount eaten by them in one day
= $$\frac{ 26\times h\times 170}{20.4h}$$
= 216.67 days
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