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Question 38
If $$8^{th}$$ February, 2005 was a Tuesday, then what was the day on $$8^{th}$$ February, 2004?
Solution
Let us assume the day on $$8^{th}$$ February, 2004 is X
And, since 2004 is a leap year so, it will have one extra day = 365+1 = 366 days till 8th February, 2005
So, number of odd days = 366/7 = 2 days
So on $$8^{th}$$ February, 2005, it will be X+2 day and it is Tuesday.
Therefore, X = Sunday
Hence, on $$8^{th}$$ February, 2004 it was sunday.
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