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Solution
Given AB + C = D................................(1
If B = 6 and D = 30, then from (1),
6A + C = 30........................(2)
and If B = 8 and D = 36,
8A + C = 36........................(3)
(3)-(2) => 2A = 6
=> A= 3
Substituting the value of A in equation (2) we get,
18 + C = 30
=> C = 12.
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