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Question 5
What is the 95th term of the following letter series?
A, A, B, B, B, B,C, C,C, C,C, C, D, D, D, D, D, D, D, D, E, ...
Solution
A - 2 terms
B - 4 terms
C - 6 terms
..
2 + 4 + 6 + ..... 2n terms => this sum should be greater than or equal to 95.
$$2\left(1+2+3+...+n\right)\ge\ 95$$
$$n\left(n+1\right)\ge\ 95$$
If n = 9, we get only 90 terms.
95th term occurs when n = 10, i.e. J.
The answer is option C.
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