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Question 10
The work done by a man, woman and child are in the ratio 3: 2:1. If daily wages of 20 men, 30 women and 36 children amount to 78/-, what will be the wages of 15 men, 21 women and 30 children for 18 weeks ?
Solution
Let the efficiency of a man, woman and child be $$3x,2x,x$$ espectively.
Thus, 1 day wage = $$(3x\times20)+(2x\times30)+(x\times36)=78$$
=> $$156x=78$$
=> $$x=\frac{1}{2}$$
$$\therefore$$ Wages of 15 men, 21 women and 30 children for 18 weeks = $$[(15\times3x)+(21\times2x)+(30\times x)]\times18\times7$$
= $$117\times\frac{1}{2}\times126$$
= $$117\times63=Rs.$$ $$7,371$$
=> Ans - (A)
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