X and Y are running towards each other from their houses. X can reach Y’s house in 25 minutes which is half the time taken by Y to run from his house to X’s house. If the two start to run towards each otherat the same time, then how much more time it will be required by Y to reach the middle of houses ?
Time taken by X to reach Y's house = 25 minutes and by Y to reach X's house = 50 min
Ratio of time taken = $$1:2$$
$$\because$$ speed is inversely proportional to time, let speed of X = $$2x$$ km/min and speed of Y = $$x$$ km/min and distance between their houses = $$2d$$ km
Using, speed = distance/time
=> $$x=\frac{2d}{50}=\frac{d}{25}$$
=> $$\frac{d}{x}=25$$ -------------(i)
Now, time taken by Y to travel $$d$$ km, i.e. mid way = $$\frac{d}{x}$$
= $$25$$ minutes
Now, time taken by X to travel $$d$$ km, i.e. mid way = $$\frac{d}{2x}$$
= $$12.5$$ minutes
So, the correct answer is $$25-12.5=12.5$$ minutes
=> Ans - (D)
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