The least number of square tiles required to pave the floor of a room 15 m 91 cm and 9 m 46 cm broad is
Let the number of square tiles be n and the area of each square tile be $$x^2$$
Length = 1591 cm
Breadth = 946 cm
x is the H.C.F of 1591 and 946.
$$1591$$ =Â $$43\times37$$
$$946$$ =Â $$43\times2\times11$$
x = 43
n(43)(43) = (1591)(946)
n = 37*22 = 814
The answer is option A.
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