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Question 17
A cylindrical vessel of radius 4 cm contains water. A solid sphere of 3 cm radius is lowered into the water until it is completely immersed . The water level in the vessel will rise by :
Solution
The volume of the sphere =Â $$\dfrac{4}{3}\times\ \pi\ \times\ \left(3\right)^3=36\pi\ $$
Now, the water level will increase equal to the volume of the sphere.Â
Let the water level increasing by h cm.
Therefore, $$36\pi\ =\pi\ \times\ \left(4\right)^2\times h$$
$$h=\dfrac{9}{4}$$
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