Question 18

Find the number of permutations that can be made from the letters of the word OMEGA, if the vowels occupy odd places.

Solution

"OMEGA" comprises 5 letters: O, M, E, G, A.

Vowels: O, E, A (3 vowels)

Consonants: M, G (2 consonants)

Odd positions in a 5-letter word are: 1st, 3rd, and 5th.

    The vowels O, E, and A can be placed in these positions in 3! = 6 ways.

    The even positions are 2 and 4.

    The consonants M and G can be arranged in these positions in 2! = 2 ways.

    The total number of arrangements is the product of the arrangements of vowels and consonants = 3! x 2! = 6*2 = 12 ways.


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