A mixture of petrol and kerosene weighing 5 kg contains 5% kerosene. How much more kerosene (approx.) must be added into it to make it 10%?
Initial amount of Kerosene(I) = 5% of 5 kg mixture of petrol and kerosene = $$\frac{5}{100}\times 5000 = 250$$ grams
Let say 'x' gm of Kerosene is added to the mixture.
The final amount of Kerosene in the mixture after the addition is given as 10%.
$$\Rightarrow \frac{250 + x}{5000 + x} = \frac{10}{100}$$
$$\Rightarrow 2500 + 10x = 5000 + x$$
$$\Rightarrow 9x = 2500$$
$$\Rightarrow x = 275$$ gm approximately.
Therefore additionally 275 gm of kerosene is to be added to the mixture to make it 10%.
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